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F i v e remove the 2 letters f and e from five and you have iv which is the roman numeral for four How can one take 2 from 5 and still be left with 4 So let's say you have a physical set of house numbers
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1,2,3,4,5 and you take 2 out then then you'll have 4 numbers left Our focus is on a seemingly magical mathematical question So you're taking 2 away from the five numbers and you end up with 4 left over.
By taking the letters 'f' and 'e' from 'five,' you are left with 'iv,' which is the roman numeral for 4
This demonstrates a playful manipulation of language rather than a straightforward mathematical operation The question 'how can you take 2 from 5 and leave 4?' is actually a riddle. The answer to the riddle “from what number can you take half and leave nothing?” is the number 8, because when either the top or bottom half of the digit is removed, the remaining half forms the number zero, or nothing. For example, 12's factors are 1 x 12, 2 x 6, and 3 x 4 (6 total factors)
On the other hand, 16's factors are 1 x 16, 2 x 8, and 4 x 4 (5 total factors) So lockers 1, 4, 9, 16, 25, etc.will all be open Since 1,000,000 is a square number (1000 x 1000), it will be open as well. In roman numerals, the number 5 is represented as “v.” if you take away 2 (which is represented as “ii”) from “v,” you can visualize it as removing the two lines that form the letter “v.” when you do this, you’re left with “iv,” which is the roman numeral for 4.
Answer to the riddle how can you take 2 from 5 and leave 4?
It is f i v e. You take 4 times 5 which is 20 then 3 plus 2 which is 5 Add 20 plus 5 and you get 25 It would take 8 2's and 5 4's to build it.
How can you take 2 from 5 and leave 4?
